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\noindent \hfill
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\begin{equation*} \begin{array}{rlrl} \vspace{0.75in}
 1. & f(x) = 3x^2-\ln(x)+e^x+5x-2 & \qquad \qquad 2. & f(x) = \sqrt{x} + \frac{2}{x} -3x^5 \\ \vspace{0.65in}
 3. & y = x^3e^x                  & \qquad \qquad 4. & y = \frac{x^2+1}{x^3-2x+1}          \\ \vspace{0.65in}
 5. & y = (\ln(x)+2x-7)^4         & \qquad \qquad 6. & f(x) = \ln\left(\frac{x^2-2}{e^{3x}}\right) \\ \vspace{0.65in}
 7. & y = \ln(4x^3(x^2+1))        & \qquad \qquad 8. & f(x) = \frac{\sqrt{x}}{x^3}+e^{-2x+\ln(3x)}  \\ \vspace{0.65in}
 9. & f(x) = \ln(\sqrt{x^3-x}+e^{5x}) & \qquad \qquad 10. & y = e^{e^{e^x}}                 \\ \vspace{0.65in}
11. & y = x^3\ln(x+3)e^{-x}       & \qquad \qquad 12. & f(x) = \frac{\ln(3x+2)}{e^x+x}     \\ \vspace{0.65in}
13. & y = \ln(\sqrt{x}e^{x^2-2x}) & \qquad \qquad 14. & f(x) = (\ln(e^x+1))^4              \\ \vspace{0.5in}
\end{array} \end{equation*}

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\noindent
Find an equation for the line tangent to $y=f(x)$ at the given point.
\begin{equation*} \begin{array}{lclc} \vspace{0.5in}
y=x^2, \qquad x=2 & \qquad \qquad \qquad & y=\ln(x), \qquad x=1 & \qquad \qquad \\ \vspace{0.65in}
y=e^x, \qquad x=0 & \qquad \qquad \qquad & y=\sqrt{x}, \qquad x=9 & \qquad \qquad  
\end{array}\end{equation*}

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